x^2-2.5x+1.25625=0

Solution for x^2-2.5x+1.25625=0 equation:

x^2-2.5x+1.25625=0

a = 1; b = -2.5; c = +1.25625;
Δ = b2-4ac
Δ = -2.52-4·1·1.25625
Δ = 1.225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{1.225}}{2*1}=\frac{2.5-\sqrt{1.225}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{1.225}}{2*1}=\frac{2.5+\sqrt{1.225}}{2}
$